Use the table to answer the question.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the
results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red
balls in Bowl B?
(1 point)
200
100
300
50
The total number of balls selected from Bowl B is 60 (white balls) + 40 (red balls) = 100 balls.
The percentage of white balls in Bowl B is 60/100 = 0.6, or 60%.
Given that Bowl B contains 500 balls, the estimated number of white balls in Bowl B is 500 * 0.6 = 300 white balls.
Similarly, the estimated number of red balls in Bowl B is 500 * 0.4 = 200 red balls.
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 300 - 200 = 100.
Therefore, the answer is 100, which is the estimated difference in the expected number of white and red balls in Bowl B.