Bowls a and b contain a number of white and red balls. Clark repeatedly selected 100 balls from bothe bowls and recorded the result in a table. Clarks pulles from Bowl A 45 white balls and 55 red balls, bowl B 60 white balls and 40 red balls. If there are 500 balls in bowl B, what it the estimated difference in the expected number of white and red balls in bowl B?
A. 300
B. 200
C. 100
D.50
B. 200
The total number of balls in bowl A can be calculated by dividing the number of white balls pulled by the proportion of white balls in the sample:
Total balls in bowl A = 100 / 0.45 = 222.22 (approximately 222)
Therefore, the estimated number of red balls in bowl A is:
222 - 45 = 177
The proportion of white balls in bowl B can be calculated as:
60 / 100 = 0.6
Since there are 500 balls in bowl B, the estimated number of white balls in bowl B is:
500 * 0.6 = 300
The estimated number of red balls in bowl B is:
500 - 300 = 200
The estimated difference in the expected number of white and red balls in bowl B is:
300 - 200 = 100
Therefore, the correct answer is C. 100.