Bowls a and b contain a number of white and red balls. Clark repeatedly selected 100 balls from bothe bowls and recorded the result in a table. Clarks pulles from Bowl A 45 white balls and 55 red balls, bowl B 60 white balls and 40 red balls. If there are 500 balls in bowl B, what it the estimated difference in the expected number of white and red balls in bowl B?
From Clark's selections, we can estimate the proportion of white balls in Bowl A to be 45/100 = 0.45, and the proportion of white balls in Bowl B to be 60/100 = 0.6.
Since Bowl A and Bowl B both contain a total of 100 balls, we can estimate the number of white balls in Bowl A to be 0.45 * 100 = 45 white balls and the number of white balls in Bowl B to be 0.6 * 100 = 60 white balls.
Since Bowl B contains 500 balls, we can estimate the number of red balls in Bowl B to be 500 - 60 = 440 red balls.
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 60 - 440 = -380.
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 380 red balls.