Use the table to answer the question.
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
A- 100
B- 300
C- 50
D- 200
Bowl B has a total of 500 balls, so the expected number of white balls in Bowl B is:
(60/100) x 500 = 300
And the expected number of red balls in Bowl B is:
(40/100) x 500 = 200
The estimated difference between these two numbers is:
300 - 200 = 100
Therefore, the answer is A- 100.
Yes, I'm sure. The answer is A- 100.
I calculated the expected number of white and red balls in Bowl B based on the given information in the table.
For Bowl B:
- The total number of balls is 500.
- The proportion of white balls is 60/100 or 0.6.
- The proportion of red balls is 40/100 or 0.4.
So, the expected number of white balls in Bowl B is:
0.6 x 500 = 300
And the expected number of red balls in Bowl B is:
0.4 x 500 = 200
The estimated difference in the expected number of white and red balls in Bowl B is:
300 - 200 = 100
Therefore, the answer is A- 100.
u sure
And how do you know
To find the estimated difference in the expected number of white and red balls in Bowl B, we need to calculate the average number of white and red balls selected from each bowl and then find the difference.
From the table, we know that Clark selected 45 white balls from Bowl A and 55 red balls from Bowl A. Similarly, he selected 60 white balls from Bowl B and 40 red balls from Bowl B.
To calculate the average number of white balls selected from each bowl, we need to divide the total number of white balls selected from each bowl by the number of times Clark selected a ball.
For Bowl A:
Average number of white balls = Total number of white balls selected / Number of times Clark selected a ball
Average number of white balls from Bowl A = 45 / (45 + 55) = 45 / 100 = 0.45 white balls per selection
Similarly, for Bowl B:
Average number of white balls from Bowl B = 60 / (60 + 40) = 60 / 100 = 0.6 white balls per selection
To find the average number of red balls selected from each bowl, we subtract the average number of white balls from 1 (since the total number of balls is 1).
For Bowl A:
Average number of red balls from Bowl A = 1 - 0.45 = 0.55 red balls per selection
For Bowl B:
Average number of red balls from Bowl B = 1 - 0.6 = 0.4 red balls per selection
Now, to find the estimated difference in the expected number of white and red balls in Bowl B, we subtract the average number of red balls from the average number of white balls for Bowl B.
Estimated difference in the expected number of white and red balls in Bowl B = Average number of white balls from Bowl B - Average number of red balls from Bowl B
Estimated difference = 0.6 - 0.4 = 0.2 white balls per selection
To convert this to the total number of white balls, we multiply by the total number of selections by Clark, which we can assume to be equal for both bowls (as it is not specified otherwise).
Estimated difference = 0.2 * (45 + 55) = 0.2 * 100 = 20 white balls
Since we know that there are 500 balls in Bowl B, the estimated difference in the expected number of white and red balls in Bowl B is:
Estimated difference = (20 / 100) * 500 = 0.2 * 500 = 100
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 100.
Answer: A- 100