Use the table to answer the question. Number of White Balls Selected Number of Red Balls SelectedBowl A 45 55Bowl B 60 40Bowls A and B contain a number of white and red balls. Clark repeatedly selected a ball from both bowls and recorded the results in a table. If there are 500 balls in Bowl B, what is the estimated difference in the expected number of white and red balls in Bowl B?
To find the estimated difference in the expected number of white and red balls in Bowl B, we first need to calculate the expected number of white and red balls in Bowl B.
From the table, we know that Clark selected 60 white balls and 40 red balls from Bowl B.
If there are 500 balls in Bowl B, we can set up a proportion to find the estimated number of white balls:
60 white balls / 100 total balls = x white balls / 500 total balls
Cross multiply to get:
100x = 30,000
x = 300
Therefore, the estimated number of white balls in Bowl B is 300, and the estimated number of red balls in Bowl B is 500 - 300 = 200.
The estimated difference in the expected number of white and red balls in Bowl B is:
300 (white balls) - 200 (red balls) = 100 balls.
wrong
I apologize for the error in my previous response. Let's correct the calculation:
Based on the information provided:
- Bowl A contains 100 balls in total
- Bowl B contains 500 balls in total
From Clark's selections, we know that 45 white balls and 55 red balls were selected from Bowl A, and 60 white balls and 40 red balls were selected from Bowl B.
To find the estimated difference in the expected number of white and red balls in Bowl B, first, we calculate the expected number of white and red balls in Bowl B:
- For Bowl A:
The proportion of white balls in Bowl A is:
45 white balls / 100 total balls = x white balls / 500 total balls
Solving for x:
x = (45/100) * 500
x = 225
Therefore, the estimated number of white balls in Bowl A is 225, and the estimated number of red balls in Bowl A is 500 - 225 = 275.
- For Bowl B:
The proportion of white balls in Bowl B is:
60 white balls / 100 total balls = x white balls / 500 total balls
Solving for x:
x = (60/100) * 500
x = 300
Therefore, the estimated number of white balls in Bowl B is 300, and the estimated number of red balls in Bowl B is 500 - 300 = 200.
Now, the estimated difference in the expected number of white and red balls in Bowl B is:
300 (white balls) - 200 (red balls) = 100 balls.
Therefore, the estimated difference in the expected number of white and red balls in Bowl B is 100 balls. Thank you for your patience.