Use the tables to answer the question.
Simon’s Results
Number of White Balls Selected Number of Red Balls Selected
Bowl A 5 15
Bowl B 16 4
Clark’s Results
Number of White Balls Selected Number of Red Balls Selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain a number of white and red balls. Simon and Clark repeatedly selected a ball from both bowls and recorded the results in a table. Whose results will give you a better indication about the proportion of white and red balls in each bowl? Explain your answer.
(1 point)
Responses
A- Both results can be used, as they performed the experiment at random.
B- Clark’s experiment. He conducted a greater number of trials than Simon.
C- Simon’s experiment. He conducted a greater number of trials than Clark.
D- Neither; they conducted the same number of trials.
B- Clark’s experiment. He conducted a greater number of trials than Simon.Clark’s results will give a better indication about the proportion of white and red balls in each bowl because he conducted a greater number of trials, making his results more reliable and representative of the true proportion in each bowl. Simon’s results only represent a small sample size and may not be as accurate.
To determine which results give a better indication of the proportion of white and red balls in each bowl, we need to consider the number of trials conducted by Simon and Clark.
Looking at the tables, Simon conducted a total of 20 trials (5 white balls and 15 red balls from Bowl A, and 16 white balls and 4 red balls from Bowl B). On the other hand, Clark conducted a total of 200 trials (45 white balls and 55 red balls from Bowl A, and 60 white balls and 40 red balls from Bowl B).
Since Clark conducted a significantly greater number of trials (200) compared to Simon (20), Clark's results will give a better indication of the proportion of white and red balls in each bowl. Therefore, the answer is B- Clark's experiment. He conducted a greater number of trials than Simon.