A 0.02-kilogram softball is thrown a catcher's mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher's mitt?
a 40N
b 7.8N
c 1.6N
d 8.2N
To find the force with which the ball hits the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Here, the mass of the softball is given as 0.02 kilograms and the acceleration is given as 8 meters per second squared.
So, the force (F) = mass (m) * acceleration (a)
= 0.02 kg * 8 m/s^2
= 0.16 N
Therefore, the force with which the ball will hit the catcher's mitt is 0.16N, which is approximately equal to 0.2N.
So, the correct option is d) 0.2N.
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a):
F = m * a
Given:
Mass (m) = 0.02 kg
Acceleration (a) = 8 m/s^2
Substituting the given values into the equation, we get:
F = 0.02 kg * 8 m/s^2
F = 0.16 kg⋅m/s^2
Therefore, the force with which the ball will hit the catcher's mitt is 0.16 Newtons (N).
The closest option is c) 1.6N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a). In this case, the mass of the softball is 0.02 kilograms and the acceleration is 8 meters per second squared.
So we can calculate the force (F) as follows:
F = m * a
F = 0.02 kg * 8 m/s^2
F = 0.16 N
Therefore, the ball will hit the catcher's mitt with a force of 0.16 Newtons (N).