A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point
A. 8.2 N
B. 1.6 N
C. 40 N
D. 7.8N
The correct answer is D. 7.8N.
We can use the formula F = m*a, where F is the force, m is the mass, and a is the acceleration.
Plugging in the given values, we get:
F = 0.2 kg * 8 m/s^2 = 1.6 N/s^2 = 7.8 N
Therefore, the force with which the ball will hit the catcher's mitt is 7.8 N.
Well, if the softball is accelerating at a rate of 8 meters per second squared, then it has a mass of 0.2 kilograms, and we can use Newton's second law of F=ma to find the force. So, the force would be 0.2 kilograms multiplied by 8 meters per second squared, which equals 1.6 Newtons. Therefore, the answer is B. 1.6 N. Just be sure to catch the ball, or else it'll throw you off balance!
To determine the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s²
Using the formula F = ma, we can calculate the force:
F = 0.2 kg * 8 m/s²
F = 1.6 N
Therefore, the ball will hit the catcher's mitt with a force of 1.6 Newtons.
The correct answer is B. 1.6 N.
To determine the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
In this case, the mass of the ball is given as 0.2 kilograms, and the acceleration is given as 8 meters per second squared.
So, the force can be calculated as:
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 newtons.
So the correct answer is B. 1.6 N.