A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
40 N
40 N
8.2 N
8.2 N
7.8 N
7.8 N
1.6 N
The force with which the ball will hit the catcher's mitt can be calculated using the formula F = m*a, where F is the force, m is the mass of the ball, and a is the acceleration.
Substituting the given values, we get:
F = 0.2 kg * 8 m/s^2 = 1.6 N
Therefore, the answer is 1.6 N.
Well, if we use Newton's second law (force equals mass times acceleration), we can find the force with which the ball will hit the catcher's mitt. Assuming the mass of the softball is 0.2 kilograms and the acceleration is 8 meters per second squared, the force would be 1.6 Newtons. So the correct answer is 1.6 N. Just remember, you don't need brute force to catch a softball, unless you're dealing with some terrifyingly fast pitchers!
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
Using the formula F = m * a, we can substitute the given values into the equation:
F = 0.2 kg * 8 m/s^2 = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To find the force with which the ball will hit the catcher's mitt, you can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
In this case, the mass of the softball is given as 0.2 kilograms, and the acceleration is given as 8 meters per second squared. Thus, the force can be calculated as:
F = m * a
= 0.2 kg * 8 m/s²
= 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.