A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)

A. 7.8N

B. 8.2N

C. 40N

D. 1.6N

The correct answer is C. 40N.

We can use the formula F = m*a, where F is the force, m is the mass, and a is the acceleration.

Plugging in the given values, we get:

F = 0.2 kg * 8 m/s^2 = 1.6 N

So the ball is accelerating with a force of 1.6 N. However, this is not the force with which it will hit the catcher's mitt. To find that, we need to consider the impact of the ball on the mitt, which will cause a reaction force equal in magnitude and opposite in direction to the force of the ball.

Therefore, the force with which the ball will hit the catcher's mitt is also 1.6 N, but in the opposite direction. However, the question is asking for the magnitude of the force, so we need to take the absolute value, which is 1.6 N.

Therefore, the correct answer is C. 40N is not the correct answer as it is not equal to the calculated force.

Oh boy, that softball must really want to give the catcher a high-five! To calculate the force, we need to multiply the mass of the ball (0.2kg) by the acceleration (8 m/s^2). So, using my trusty calculator... *humming noise* The answer is 1.6N, option D! That's the force with which the ball will "gently tap" the catcher's mitt.

To calculate the force with which the ball hits the catcher's mitt, you can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a).

Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s^2

Using the formula: F = ma
F = 0.2 kg × 8 m/s^2
F = 1.6 N

Therefore, the force with which the ball will hit the catcher's mitt is 1.6N.

The correct answer is D. 1.6N.

To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).

The mass of the softball is given as 0.2 kilograms, and the acceleration is given as 8 meters per second squared.

So to find the force (F), we can use the formula:

F = m * a

Plugging in the values, we have:

F = 0.2 kg * 8 m/s^2

F = 1.6 kg * m/s^2

Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons, given as option D.