A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
1.6 N
1.6 N
40 N
40 N
7.8 N
7.8 N
8.2 N
The force with which the ball will hit the catcher's mitt is calculated using the formula: force = mass x acceleration. In this case, the mass is 0.2 kilograms and the acceleration is 8 meters per second squared. Thus, the force will be:
force = 0.2 kg x 8 m/s^2 = 1.6 N
Therefore, the answer is 1.6 N.
To determine the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of the softball (m) = 0.2 kilograms
Acceleration of the softball (a) = 8 meters per second squared
Therefore,
F = m x a
F = 0.2 kg x 8 m/s²
F = 1.6 N
So, the ball will hit the catcher's mitt with a force of 1.6 Newtons.
To calculate the force with which the ball will hit the catcher's mitt, you can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
Using the formula: F = m * a, we can substitute the given values:
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.