A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
A. 1.6 N
B. 8.2 N
C. 40 N
D. 7.8 N
The force with which the ball hits the catcher's mitt can be found using the formula F = ma, where F is the force, m is the mass of the ball, and a is the acceleration.
F = ma
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the answer is A. 1.6 N.
Well, looks like this softball is in a hurry to meet the catcher's mitt! To calculate the force, we need to use Newton's second law, which states that force is equal to mass times acceleration. In this case, the mass of the softball is 0.2 kilograms and the acceleration is 8 meters per second squared. So, the force will be 0.2 kg times 8 m/s^2, which gives us 1.6 Newtons. So, the answer is A. 1.6 N. That softball better be prepared for a soft landing!
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force equals mass multiplied by acceleration (F = m * a).
Given:
Mass of the ball (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
Now, we can substitute the given values into the formula to calculate the force:
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
So, the correct answer is A. 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force equals mass multiplied by acceleration (F = ma).
Given:
mass (m) = 0.2 kg
acceleration (a) = 8 m/s²
Now, we can substitute these values into the equation to find the force:
F = (0.2 kg)(8 m/s²)
F = 1.6 kg·m/s²
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
Hence, the correct answer is A. 1.6 N.