A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
40 N
40 N
8.2 N
8.2 N
1.6 N
1.6 N
7.8 N
To calculate the force with which the ball will hit the catcher's mitt, we can use the formula:
Force = mass * acceleration.
Given that the mass of the ball is 0.2 kilograms and the acceleration is 8 meters per second squared, we can substitute these values into the formula:
Force = 0.2 kg * 8 m/s^2
Calculating this, we get:
Force = 1.6 N.
Therefore, the correct answer is 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of the softball (m) = 0.2 kg
Acceleration of the softball (a) = 8 m/s^2
Using the formula F = m * a, we can calculate the force:
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m * a
In this case, the mass of the softball is given as 0.2 kilograms, and the acceleration is given as 8 meters per second squared. Plugging these values into the equation:
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.