Rectangle ABCD has vertices point A (−5, 1), point B (-2, 1), point
C (-2, 6), and point D (−5, 6). Find the perimeter of the rectangle in feet.
(1 point)
To find the perimeter of the rectangle, we need to add the lengths of all four sides.
Using the distance formula: d = √[(x2 - x1)^2 + (y2 - y1)^2]
Side AB: √[(-2 - (-5))^2 + (1 - 1)^2] = √[3^2 + 0^2] = √9 = 3
Side BC: √[(-2 - (-2))^2 + (6 - 1)^2] = √[0^2 + 5^2] = √25 = 5
Side CD: √[(-5 - (-2))^2 + (6 - 6)^2] = √[3^2 + 0^2] = √9 = 3
Side DA: √[(-5 - (-5))^2 + (1 - 6)^2] = √[0^2 + (-5)^2] = √25 = 5
Adding the lengths of all four sides:
Perimeter = AB + BC + CD + DA = 3 + 5 + 3 + 5 = 16
Therefore, the perimeter of the rectangle is 16 feet.