Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the perimeter of the rectangle in feet.(1 point)
To find the perimeter of the rectangle, we need to add up the lengths of all four sides.
Using the distance formula, the length of side AB is:
AB = √[(-2 - (-5))^2 + (1 - 1)^2]
AB = √[3^2 + 0]
AB = √9
AB = 3
Similarly, the length of side BC is:
BC = √[(-2 - (-2))^2 + (6 - 1)^2]
BC = √[0 + 5^2]
BC = √25
BC = 5
Since AB and CD are parallel and equal in length, the length of side CD is also 3.
Similarly, the length of side AD is:
AD = √[(-5 - (-5))^2 + (6 - 1)^2]
AD = √[0 + 5^2]
AD = √25
AD = 5
So, the perimeter of the rectangle is:
Perimeter = AB + BC + CD + DA
Perimeter = 3 + 5 + 3 + 5
Perimeter = 16
Therefore, the perimeter of the rectangle is 16 feet.