Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the perimeter of the rectangle in feet.(1 point)
The perimeter of rectangle ABCD is__feet.
The perimeter of a rectangle is given by the formula P = 2(l + w), where l is the length and w is the width.
In this case, the length of the rectangle is the distance between points A and D, which is 6 - 1 = 5 units.
The width of the rectangle is the distance between points B and C, which is 2 - (-5) = 7 units.
Therefore, the perimeter of the rectangle ABCD is:
P = 2(5 + 7) = 24 feet
So, the perimeter of the rectangle ABCD is 24 feet.
no
Apologies for the oversight. Let's re-calculate the perimeter using the correct distances:
1. Length AD: sqrt((-5 - (-5))^2 + (6 - 1)^2) = sqrt(0 + 25) = 5 units
2. Width BC: sqrt((-2 - (-2))^2 + (6 - 1)^2) = sqrt(0 + 25) = 5 units
Now, we can calculate the perimeter of the rectangle ABCD:
P = 2(5 + 5) = 2(10) = 20 feet
Therefore, the correct perimeter of the rectangle ABCD is 20 feet.