Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the area of the rectangle in square feet.(1 point)
The area of rectangle ABCD is_____square feet.
The length of the rectangle is the difference in the y-coordinates of points A and B, which is 6 - 1 = 5 units.
The width of the rectangle is the difference in the x-coordinates of points A and D, which is 5 - (-5) = 10 units.
Therefore, the area of the rectangle is the length multiplied by the width, which is 5 units * 10 units = 50 square feet.
The area of rectangle ABCD is 50 square feet.
no
I apologize for the mistake in my calculations. Let me correct it.
To find the area of the rectangle, we need to calculate the length and the width of the rectangle.
Length = Distance between points A and B = |-2 - (-5)| = 3 units
Width = Distance between points A and D = |6 - 1| = 5 units
Area of the rectangle = Length * Width = 3 units * 5 units = 15 square units
Therefore, the area of rectangle ABCD is 15 square units.