Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the area of the rectangle in square feet.(1 point)
To find the area of the rectangle, we need to find the length and width of the rectangle first.
The length of the rectangle is the distance between points A and D. Using the distance formula:
length = √((-2 - (-5))^2 + (6 - 1)^2)
= √(3^2 + 5^2)
= √(9 + 25)
= √34
The width of the rectangle is the distance between points A and B. Using the distance formula:
width = √((-2 - (-5))^2 + (1 - 1)^2)
= √(3^2 + 0)
= 3
Now, we can find the area of the rectangle by multiplying the length and width:
area = length * width
= √34 * 3
= 3√34 square feet
Therefore, the area of the rectangle ABCD is 3√34 square feet.