Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point)
55.55 yd. 2
72.52 yd.2
43.31 yd. 2
66 yd.2
The formula to find the surface area of a rectangular pyramid is given by:
Surface area = lw + 1/2 * l * √((w/2)^2 + h^2) + 1/2 * w * √((l/2)^2 + h^2)
Given:
l = 8 yd
w = 4 yd
h = 2 yd
Surface area = 8 * 4 + 1/2 * 8 * √((4/2)^2 + 2^2) + 1/2 * 4 * √((8/2)^2 + 2^2)
Surface area = 32 + 1/2 * 8 * √(4 +4) + 1/2 * 4 * √(16 + 4)
Surface area = 32 + 1/2 * 8 * √(8) + 1/2 * 4 * √(20)
Surface area = 32 + 4 * √(8) + 2 * √(20)
Surface area ≈ 55.55 yd2
Therefore, the surface area of the rectangular pyramid is approximately 55.55 yd2.
The correct answer is:
55.55 yd. 2