Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point)
Responses
72.52 yd.2
72.52 yd. 2
66 yd.2
66 yd. 2
43.31 yd.2
43.31 yd. 2
55.55 yd.2
55.55 yd. 2
To find the surface area of a rectangular pyramid, we need to calculate the area of each face and then add them together.
The base of the pyramid is a rectangle, so the area of the rectangular base is l * w = 8 * 4 = 32 yd^2.
The pyramid has 4 triangular faces with the same dimensions. To calculate the area of one triangular face, we can use the formula: A = 1/2 * base * height.
The base of each triangular face is the same as the width of the base of the pyramid, so it is 4 yd. The height is given as 2 yd.
The area of each triangular face is: A = 1/2 * 4 * 2 = 4 yd^2.
Since there are 4 triangular faces, the total area of the 4 triangular faces is 4 * 4 = 16 yd^2.
To find the total surface area, we add the area of the base and the area of the triangular faces together:
32 + 16 = 48 yd^2.
Therefore, the surface area of the rectangular pyramid is 48 yd^2.