Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point)
A. 43.31 yd.^2
B. 55.55 yd.^2
C. 72.52 yd.^2
D. 66 yd.^2
To find the surface area of a rectangular pyramid, we need to find the area of the base and the area of the four triangular faces.
The area of the base can be found by multiplying the length (l) by the width (w):
Base Area = l * w = 8 yd. * 4 yd. = 32 yd.^2
The area of each triangular face can be found by multiplying half the base length (l) by the height (h):
Triangular Face Area = (1/2) * l * h = (1/2) * 8 yd. * 2 yd. = 8 yd.^2
There are four triangular faces, so the total area of the four triangular faces is:
4 * Triangular Face Area = 4 * 8 yd.^2 = 32 yd.^2
To find the surface area, we need to add the area of the base to the area of the four triangular faces:
Surface Area = Base Area + Total Triangular Face Area = 32 yd.^2 + 32 yd.^2 = 64 yd.^2
The surface area of the rectangular pyramid is 64 yd.^2.
Therefore, the answer is not listed among the given options.