Find the surface area of a rectangular pyramid with these measurements: l = 15 m, w = 12 m, and h = 10 m. Express your answer as a decimal rounded to the nearest hundredth.
To find the surface area of a rectangular pyramid, we need to find the area of each face and sum them.
The base of the pyramid is a rectangle with dimensions 15 m and 12 m, so its area is length times width: 15 m * 12 m = 180 m^2.
The other four faces are triangles with height 10 m and base 15 m or 12 m.
The area of each triangle is 1/2 * base * height = 1/2 * 15 m * 10 m = 75 m^2.
So, the total surface area is 180 m^2 (for the base) + 2 * 75 m^2 (for the two triangles with base 15 m) + 2 * 75 m^2 (for the two triangles with base 12 m).
The sum is 180 m^2 + 150 m^2 + 150 m^2 = 480 m^2.
Therefore, the surface area of the rectangular pyramid is 480 m^2. Answer: \boxed{480}.