Find the surface area of a rectangular pyramid with these measurements: l
= 8 yd., w
= 4 yd., and h
= 2 yd.(1 point)
Responses
66 yd.2
66 yd. 2
43.31 yd.2
43.31 yd. 2
55.55 yd.2
55.55 yd. 2
72.52 yd.2
To calculate the surface area of a rectangular pyramid, we need to find the area of the base and the areas of the four triangular faces.
The area of the base (rectangle) is l * w = 8 yd * 4 yd = 32 yd^2.
The area of each triangular face can be found using the formula A = (1/2) * base * height. Since the base of each triangular face is equal to the length of the rectangle (8 yd) and the height is equal to the height of the pyramid (2 yd), the area of each triangular face is (1/2) * 8 yd * 2 yd = 8 yd^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 8 yd^2 = 32 yd^2.
Adding the area of the base and the area of the triangular faces, the surface area of the rectangular pyramid is 32 yd^2 + 32 yd^2 = 64 yd^2.
Therefore, the correct response is 64 yd^2.
Choose one of the answers above
I apologize for the incorrect response in my previous message. The correct answer is:
66 yd^2.