Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point)
The surface area of a rectangular pyramid is calculated by adding the area of the base to the sum of the areas of the four triangular faces.
The base of the rectangular pyramid is a rectangle with length 8 yd and width 4 yd.
The area of the base is therefore 8 yd * 4 yd = 32 yd^2.
Each triangular face of the pyramid has the same base as the rectangle and a height of 2 yd.
The area of each triangular face is given by the formula 1/2 * base * height, so the area of each triangular face is 1/2 * 8 yd * 2 yd = 8 yd^2.
Since there are four triangular faces, the total area of the four triangular faces is 4 * 8 yd^2 = 32 yd^2.
Finally, we can find the total surface area of the rectangular pyramid by adding the area of the base to the sum of the areas of the triangular faces:
Surface area = base area + sum of triangular face areas
Surface area = 32 yd^2 + 32 yd^2 = 64 yd^2.
Therefore, the surface area of the rectangular pyramid is 64 square yards. Answer: \boxed{64}.