Identify the zeros of the following quadratic function equation y=-(x-2)^2+4 answer in series notation
The zeros of the function can be found by setting y equal to zero and solving for x:
0 = -(x-2)^2 + 4
-(x-2)^2 = -4
(x-2)^2 = 4
x-2 = ±2
x = 2 ± 2
Therefore, the zeros of the function are x = {0, 4}.
Answer in series notation: {0, 4}