Question 37
Identify the zeros of the following quadratic equation. Answer in series notation { }
y=-(x-2^2+4
To find the zeros of the quadratic equation, we need to set y = 0 and solve for x.
0 = -(x^2 - 4x + 4)
0 = x^2 - 4x + 4
Next, we can factorize the equation:
0 = (x - 2)(x - 2)
0 = (x - 2)^2
Therefore, the zeros of the quadratic equation are: {2}