Question 37
Identify the zeros of the following quadratic equation. Answer in series notation { }
*
y=-(x-2)^2+4
The zeros of the quadratic equation can be found by setting y = 0 and solving for x.
0 = -(x-2)^2 + 4
(x-2)^2 = 4
x-2 = ±√4
x-2 = ±2
This gives us two zeros: x = 2+2 and x = 2-2
Therefore, the zeros of the quadratic equation in series notation are {4, 0}.