Identify the zeros of the following quadratic equation. Answer in series notation {}
y = −(x – 2)² + 4
{2}
(x-2)^2 = 4
x-2 = 2
or
x-2 = -2 (because (-2)^2 = +
so
x = 4
or x = 0
y = −(x – 2)² + 4
x-2 = 2
or
x-2 = -2 (because (-2)^2 = +
so
x = 4
or x = 0