Rectangle ABCD has vertices point A ( -5,1) point B (-2,1) point C (-2,6) and point D (-5,6) find the perimeter of the rectangle in feet
To find the perimeter of the rectangle, we need to calculate the distance between each pair of consecutive points, and then sum them up.
The distance formula between two points (x1, y1) and (x2, y2) is given by:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Thus,
AB = sqrt((-2 - (-5))^2 + (1 - 1)^2) = sqrt(3^2) = 3
BC = sqrt((-2 - (-2))^2 + (6 - 1)^2) = sqrt(5^2) = 5
CD = sqrt((-5 - (-2))^2 + (6 - 6)^2) = sqrt(3^2) = 3
DA = sqrt((-5 - (-5))^2 + (6 - 1)^2) = sqrt(5^2) = 5
The perimeter of the rectangle is the sum of the distances:
Perimeter = AB + BC + CD + DA
Perimeter = 3 + 5 + 3 + 5
Perimeter = 16 feet
Therefore, the perimeter of the rectangle ABCD is 16 feet.