Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the perimeter of the rectangle in feet.(1 point)
The perimeter of rectangle ABCD is
feet.
wrong try again
The length of the rectangle is the distance between points A and D, which can be found using the distance formula:
d = √[(x2 - x1)^2 + (y2 - y1)^2]
d = √[(-5 - (-5))^2 + (6 - 1)^2] = √[0 + 25] = √25 = 5 feet
The width of the rectangle is the distance between points B and C, which can also be found using the distance formula:
d = √[(-2 - (-2))^2 + (6 - 1)^2] = √[0 + 25] = √25 = 5 feet
Since the perimeter of a rectangle is the sum of all its sides, we can calculate it as:
Perimeter = 2*(Length + Width) = 2*(5 + 5) = 2*10 = 20 feet
Therefore, the perimeter of rectangle ABCD is 20 feet.
My apologies for the mistake. Let's try again.
The length of the rectangle is the distance between points A and D:
d = √[(-5 - (-5))^2 + (6 - 1)^2]
d = √[0 + 25]
d = √25
d = 5 feet
The width of the rectangle is the distance between points B and C:
d = √[(-2 - (-2))^2 + (6 - 1)^2]
d = √[0 + 25]
d = √25
d = 5 feet
The perimeter of the rectangle is the sum of all its sides:
Perimeter = 2*(Length + Width)
Perimeter = 2*(5 + 5)
Perimeter = 2*(10)
Perimeter = 20 feet
Therefore, the correct perimeter of rectangle ABCD is 20 feet.