a public aquarium is being built to contain neon tetras each neon tetra needs 1.25 galloons of water. the aquarium will contain 1x10^5 galloons of water. how many tetras can it house. write the answer in scientific notation
The number of neon tetras that can be housed in the aquarium can be calculated by dividing the total volume of water in the aquarium by the volume of water needed for each tetra:
1x10^5 gallons / 1.25 gallons/tetra = 8x10^4 tetras
Therefore, the public aquarium can house 8x10^4 neon tetras.