A public aquarium is being built to contain neon Tetris each neon Tetra needs 1.25 gallons of water the aquarium will contain one times 10 to the power of 5 gallons of water how many tetras can it house write your answer in scientific notation
To find out how many neon Tetras can be housed in the aquarium, we need to divide the total gallons of water by the amount of water each Tetra needs.
Number of Tetras = Total Gallons of Water / Gallons of Water per Tetra
Number of Tetras = (1 * 10^5 gallons) / (1.25 gallons)
Number of Tetras = 8 * 10^4 Tetras
Therefore, the aquarium can house 8 * 10^4 neon Tetras.
To determine how many neon Tetras can be housed in the aquarium, we divide the total volume of water in the aquarium by the water requirement per neon Tetra.
Given:
Total volume of water = 1.0 × 10^5 gallons
Water requirement per neon Tetra = 1.25 gallons
To calculate the number of neon Tetras that can be housed:
Number of Tetras = Total volume of water / Water requirement per neon Tetra
Number of Tetras = (1.0 × 10^5 gallons) / (1.25 gallons)
Number of Tetras = (1.0 × 10^5) / (1.25) = 8.0 × 10^4
Therefore, the aquarium can house 8.0 × 10^4 neon Tetras.
To solve this problem, we need to divide the total volume of the aquarium by the volume needed for each neon Tetra.
First, let's convert 1.25 gallons into scientific notation:
1.25 gallons = 1.25 x 10^0 gallons
Next, we can calculate the number of neon Tetras the aquarium can house by dividing the total volume of the aquarium by the volume required for each neon Tetra:
(1.25 x 10^0) gallons / (1 x 10^5) gallons = (1.25 / 1) x (10^0 / 10^5) = 1.25 x (10^0 - 5) = 1.25 x 10^(-5)
Therefore, the public aquarium can house 1.25 x 10^(-5) neon Tetras in scientific notation.