A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1×105 gallons of water. How many tetras can it house? Write the answer in scientific notation.(1 point)
To find out how many tetras can be housed in the aquarium, we need to divide the total gallons of water in the aquarium by the amount of water needed per tetra.
Number of tetras = Total gallons of water / Gallons of water per tetra
Number of tetras = 1×105 gallons / 1.25 gallons/tetra
Number of tetras = 8×104 tetras
In scientific notation, this would be written as 8.0 × 104 tetras.
To find out how many tetras the aquarium can house, we need to divide the total gallons of water in the aquarium by the gallons of water needed per tetra.
Total gallons of water in the aquarium: 1 × 10^5 gallons
Gallons of water needed per tetra: 1.25 gallons
To find out how many tetras the aquarium can house, we can divide the total gallons of water in the aquarium by the gallons of water needed per tetra:
(1 × 10^5) / 1.25 = 8 × 10^4 tetras
Therefore, the aquarium can house 8 × 10^4 tetras.
To find out how many neon tetras can be housed in the aquarium, we need to divide the total amount of water in the aquarium by the amount of water each tetra needs.
The aquarium contains 1×10^5 gallons of water.
Each neon tetra needs 1.25 gallons of water.
To find the number of tetras, we divide the total amount of water by the amount of water each tetra needs.
Number of tetras = Total water / Water per tetra
= 1×10^5 gallons / 1.25 gallons
To divide by 1.25, we can multiply by its reciprocal, which is 0.8.
Number of tetras = (1×10^5 gallons) * (1 / 1.25 gallons)
= (1×10^5 gallons) * (0.8)
Multiplying 1×10^5 by 0.8 gives us 8×10^4.
So the number of tetras the aquarium can house is 8×10^4.
Therefore, the answer in scientific notation is 8×10^4.