A public aquarium is being built to contain neon tetras. Each neon tetra needs 1.25 gallons of water. The aquarium will contain 1×105 gallons of water. How many tetras can it house? Write the answer in scientific notation.
To find the number of tetras the aquarium can house, we need to divide the total amount of water in the aquarium by the amount of water each tetra needs.
Total number of tetras = Total amount of water / Amount of water per tetra
Total number of tetras = 1×10^5 gallons / 1.25 gallons
Total number of tetras = 8×10^4 tetras
Therefore, the aquarium can house 8×10^4 tetras.
To find out how many neon tetras the aquarium can house, we need to divide the total volume of water in the aquarium by the amount of water needed for each tetra.
Given:
Volume of water in the aquarium = 1×10^5 gallons
Water needed per neon tetra = 1.25 gallons
To calculate the number of tetras the aquarium can house, we divide the total volume of water by the water needed per tetra:
Number of tetras = Volume of water in the aquarium / Water needed per tetra
Number of tetras = 1×10^5 gallons / 1.25 gallons
Number of tetras = (1×10^5) / (1.25)
Number of tetras = 8×10^4
So, the aquarium can house 8×10^4 neon tetras.
To find out how many tetras the aquarium can house, we need to divide the total volume of water in the aquarium by the volume of water needed for each neon tetra.
The total volume of the water in the aquarium is given as 1×105 gallons, which can be written in scientific notation as 1.0 × 10^5 gallons.
The volume of water needed for each neon tetra is 1.25 gallons.
To calculate the number of tetras, we divide the total volume of water by the volume of water needed for each tetra:
Number of tetras = Total volume of water / Volume of water needed for each tetra
Number of tetras = 1.0 × 10^5 gallons / 1.25 gallons
Dividing 1.0 × 10^5 by 1.25 gives us:
Number of tetras = 8 × 10^4 tetras
Therefore, the aquarium can house 8 × 10^4 tetras.