Find the surface area of a rectangular pyramid with these measurements L = 13 m W = 11cm and h = 8 cm. Express your answer, as a DECIMAL rounded to the nearest hundredth.
The surface area of a rectangular pyramid can be found by adding the areas of the base and the four triangular faces.
The base of the pyramid is a rectangle with length L and width W, so its area is L * W.
Each triangular face has a base equal to the width of the rectangle and a height equal to the height of the pyramid. So the area of each triangular face is (1/2) * W * h.
Therefore, the surface area of the pyramid is:
L * W + 4 * (1/2) * W * h
Plugging in the given values:
Surface area = 13 m * 11 cm + 4 * (1/2) * 11 cm * 8 cm
Surface area = 143 m * cm + 4 * 5.5 m * cm
Surface area = 143 m * cm + 22 m * cm
Surface area = 165 m * cm
To convert this to a decimal and round to the nearest hundredth, we need to convert the units of cm to meters:
165 m * cm * 0.01 m/cm = 1.65 m^2
So, the surface area of the rectangular pyramid is 1.65 square meters.