Find the surface area of a rectangular pyramid with these measurements l = 8cm; w = 4 cm and h = 2cm Express your answer as a decimal rounded to the nearest hundredth 1 point)
The surface area of a rectangular pyramid can be found by adding the area of the base to the sum of the areas of the four triangular faces.
The area of the base is calculated by multiplying the length (l) by the width (w) of the rectangle:
Area of base = l * w = 8cm * 4cm = 32cm^2
The area of each triangular face can be found by calculating half the product of the base of the triangle and the height of the triangle:
Area of each triangular face = (1/2) * l * h = (1/2) * 8cm * 2cm = 8cm^2
Since there are four triangular faces, the total area of the triangular faces is:
Total area of triangular faces = 4 * Area of each triangular face = 4 * 8cm^2 = 32cm^2
Therefore, the total surface area of the rectangular pyramid is:
Total surface area = Area of base + Total area of triangular faces = 32cm^2 + 32cm^2 = 64cm^2
Rounded to the nearest hundredth, the surface area of the rectangular pyramid is 64.00 cm^2.