Find the surface area of a rectangular pyramid with these measurements, l = 8yd., w = 4 yd., h = 2 yd (you get the point of which lesson this is)
*THESE ARE ANSWERS NOT A QUESTION!*
1) 72.45 yd^2
2) 276 square yards
3) 320 ft^2
4) 55.75 in.^2
5) area of a triangle
The surface area of a rectangular pyramid is calculated by finding the area of the base and adding the areas of the four triangular faces.
First, let's find the area of the rectangular base:
Area = length * width = 8yd * 4yd = 32yd^2
Next, let's find the area of each triangular face. Since the pyramid is rectangular, we have two identical pairs of faces.
First pair of triangular faces:
Area = (1/2) * base * height = (1/2) * 8yd * 2yd = 8yd^2
Second pair of triangular faces:
Area = (1/2) * base * height = (1/2) * 4yd * 2yd = 4yd^2
Now, let's add up the areas:
Total surface area = Area of base + 2 * Area of triangular faces
Total surface area = 32yd^2 + 2(8yd^2 + 4yd^2)
Total surface area = 32yd^2 + 2(12yd^2)
Total surface area = 32yd^2 + 24yd^2
Total surface area = 56yd^2
Therefore, the surface area of the rectangular pyramid is 56yd^2.