Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point)Responses 66 yd.266 yd. 255.55 yd.255.55 yd. 243.31 yd.243.31 yd. 272.52 yd.2
The surface area of a rectangular pyramid can be found by adding the areas of all the faces.
First, let's find the area of the rectangular base:
Area of base = l * w
= 8 yd. * 4 yd.
= 32 yd.²
Next, let's find the areas of the four triangular faces:
Area of triangular face = (1/2) * base * height
= (1/2) * l * h
= (1/2) * 8 yd. * 2 yd.
= 8 yd.²
Now, let's find the total surface area by adding the areas of the base and the four triangular faces:
Total surface area = area of base + (4 * area of triangular face)
= 32 yd.² + (4 * 8 yd.²)
= 32 yd.² + 32 yd.²
= 64 yd.²
Therefore, the surface area of the rectangular pyramid is 64 yd.². Answer: \boxed{64}.