Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point)
Responses
72.52 yd.2
72.52 yd. 2
55.55 yd.2
55.55 yd. 2
43.31 yd.2
43.31 yd. 2
66 yd.2
To find the surface area of a rectangular pyramid, you need to find the area of each face and add them together.
The rectangular pyramid has a rectangular base with dimensions l = 8 yd and w = 4 yd. The area of the base is l*w = 8 yd * 4 yd = 32 yd^2.
The height of the pyramid is h = 2 yd. To find the area of each triangular face, you can use the formula for the area of a triangle: 1/2 * base * height.
There are 4 triangular faces of the pyramid.
The base of each triangular face is the length of the rectangular base, which is 8 yd.
The height of each triangular face is the height of the pyramid, which is 2 yd.
The area of each triangular face is 1/2 * 8 yd * 2 yd = 8 yd^2.
Therefore, the total area of all the triangular faces is 4 * 8 yd^2 = 32 yd^2.
To find the surface area of the entire pyramid, you need to add the area of the base and the area of the triangular faces:
Surface area = area of base + area of triangular faces
Surface area = 32 yd^2 + 32 yd^2 = 64 yd^2
Therefore, the surface area of the rectangular pyramid is 64 yd^2.