Find the surface area of a rectangular pyramid with these measurements: l = 8 yd., w = 4 yd., and h = 2 yd.(1 point)
Responses
66 yd.2
66 yd. 2
43.31 yd.2
43.31 yd. 2
72.52 yd.2
72.52 yd. 2
55.55 yd.2
55.55 yd. 2
To find the surface area of a rectangular pyramid, you need to calculate the area of each face and add them together.
The rectangle faces have dimensions l x w, so the area of each rectangle face is 8 * 4 = 32 square yards.
Since there are 2 rectangle faces, the total area of the rectangle faces is 2 * 32 = 64 square yards.
The triangle faces have a base equal to the width of the rectangle (4 yd.) and a height equal to the height of the pyramid (2 yd.).
The area of each triangle face is 1/2 * base * height = 1/2 * 4 * 2 = 4 square yards.
Since there are 4 triangle faces, the total area of the triangle faces is 4 * 4 = 16 square yards.
Adding the area of the rectangle faces and the triangle faces gives a total surface area of 64 + 16 = 80 square yards.
Therefore, the correct response is 80 yd.2.