Find the surface area of a rectangular pyramid with these measurements: l = 13 cm, w = 11 cm, and h = 8 cm. Express your answer as a decimal rounded to the nearest hundredth.
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The surface area of a rectangular pyramid can be found by adding together the areas of all the faces.
First, find the area of the base. In this case, the base is a rectangle with length 13 cm and width 11 cm. The area of a rectangle is found by multiplying the length by the width, so the area of the base is 13 cm * 11 cm = 143 cm^2.
Next, find the areas of the four triangular faces. Each of these triangles has a base equal to the length of the rectangle and a height equal to the height of the pyramid. The area of a triangle is given by the formula A = (1/2) * base * height, so the area of each triangular face is (1/2) * 13 cm * 8 cm = 52 cm^2.
Finally, add together the areas of all the faces to find the total surface area. In this case, there is one rectangular base with an area of 143 cm^2 and four triangular faces with an area of 52 cm^2 each, so the total surface area is 143 cm^2 + 4 * 52 cm^2 = 143 cm^2 + 208 cm^2 = 351 cm^2.
Therefore, the surface area of the rectangular pyramid is 351 cm^2.