Find the surface area of a rectangular pyramid with these measurements l =8 cm, w = 4 cm, and h = 2 cm express your answer as a decimal rounded to the nearest hundredth.
To find the surface area of a rectangular pyramid, we need to find the area of each face and add them together.
The base of the pyramid is a rectangle with length (l) and width (w). The area of the base is lw.
The lateral faces are triangle-shaped. Each lateral face has a base with length (l) and height (h), so the area of each lateral face is (1/2)lh.
The total surface area is:
lw + (1/2)lh + (1/2)lh + (1/2)lh
Substituting the given values:
8 cm * 4 cm + (1/2) * 8 cm * 2 cm + (1/2) * 8 cm * 2 cm + (1/2) * 8 cm * 2 cm
32 cm² + 8 cm² + 8 cm² + 8 cm²
56 cm²
Rounding to the nearest hundredth, the surface area of the rectangular pyramid is approximately 56.00 cm².
wrong
I apologize for the mistake.
To find the surface area of a rectangular pyramid, we need to find the area of each face and add them together.
The base of the pyramid is a rectangle with length (l) and width (w). The area of the base is lw.
The lateral faces are triangle-shaped. Each lateral face has a base with length (l) and height (h), so the area of each lateral face is (1/2)lh.
The total surface area is:
lw + 2*(1/2)lh
Substituting the given values:
8 cm * 4 cm + 2*(1/2) * 8 cm * 2 cm
32 cm² + 2*(1/2) * 8 cm * 2 cm
32 cm² + 2*8 cm²
32 cm² + 16 cm²
48 cm²
Rounding to the nearest hundredth, the surface area of the rectangular pyramid is approximately 48.00 cm².