Find the surface area of a rectangular pyramid with these measurements: l = 13 cm, w = 11 cm, and h = 8 cm. Express your answer as a decimal rounded to the nearest hundredth.(1 point)
cm2
wrong again. The base of the pyramid is not square, so the area is
13*11 + 2(1/2 * 11*8) + 2(1/2 * 13*8) = 335 cm^2
You are correct, I apologize for the mistake in my previous response.
The base of the pyramid is a rectangle with length 13 cm and width 11 cm, so the area of the base is 13 cm * 11 cm = 143 cm^2.
Each of the four triangular faces has a base that is one of the sides of the rectangle and a height equal to the height of the pyramid. The area of each triangle is 1/2 * base * height.
Therefore, the area of one of the triangular faces is 1/2 * 11 cm * 8 cm = 44 cm^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 44 cm^2 = 176 cm^2.
The total surface area of the rectangular pyramid is the sum of the area of the base and the area of the triangular faces, which is 143 cm^2 + 176 cm^2 = 319 cm^2.
Therefore, the correct surface area of this rectangular pyramid with the given measurements is 319 cm^2.
To find the surface area of a rectangular pyramid, you need to calculate the area of each face and then add them together.
A rectangular pyramid has 5 faces: the base and four triangular faces.
First, let's calculate the area of the base. The base of a rectangular pyramid is a rectangle, so the area is given by multiplying the length (l) by the width (w). Therefore, the area of the base is 13 cm * 11 cm = 143 cm².
Next, let's calculate the areas of the four triangular faces. Each triangular face has a base equal to the length (l) of the rectangular base and a height equal to the height (h) of the pyramid. The formula for the area of a triangle is (1/2) * base * height. Therefore, the area of each triangular face is (1/2) * 13 cm * 8 cm = 52 cm². Since there are four triangular faces, the total area of the four triangular faces is 4 * 52 cm² = 208 cm².
Finally, add the area of the base (143 cm²) to the total area of the triangular faces (208 cm²) to get the total surface area of the rectangular pyramid. 143 cm² + 208 cm² = 351 cm².
So, the surface area of the rectangular pyramid with these measurements is 351 cm², rounded to the nearest hundredth.
To find the surface area of a rectangular pyramid, we need to find the sum of the areas of all its faces.
The base of the pyramid is a rectangle with length 13 cm and width 11 cm, so the area of the base is 13 cm * 11 cm = 143 cm^2.
Each of the four triangular faces has a base that is one of the sides of the rectangle and a height equal to the height of the pyramid. The area of each triangle is 1/2 * l * h.
Therefore, the area of one of the triangular faces is 1/2 * 13 cm * 8 cm = 52 cm^2.
Since there are four triangular faces, the total area of the triangular faces is 4 * 52 cm^2 = 208 cm^2.
The total surface area of the rectangular pyramid is the sum of the area of the base and the area of the triangular faces, which is 143 cm^2 + 208 cm^2 = 351 cm^2.
Therefore, the surface area of this rectangular pyramid with the given measurements is 351 cm^2.