A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
40 N
40 N
7.8 N
7.8 N
1.6 N
1.6 N
8.2 N
The force with which the ball will hit the catcher's mitt can be calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
Force = mass × acceleration
In this case, the mass of the softball is 0.2 kilograms and the acceleration is 8 meters per second squared.
Therefore, the force with which the ball will hit the catcher's mitt is:
Force = 0.2 kg × 8 m/s^2 = 1.6 N
So, the correct answer is 1.6 N.
To calculate the force with which the ball will hit the catcher's mitt, you can use Newton's second law of motion: force (F) equals mass (m) times acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
Using the formula F = m × a, we can substitute in the given values:
F = 0.2 kg × 8 m/s^2
Calculating:
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of the softball (m) = 0.2 kilograms
Acceleration (a) = 8 meters per second squared
We can plug in the values into the formula and calculate the force:
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 Newtons
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.