A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
8.2 N
8.2 N
7.8 N
7.8 N
1.6 N
1.6 N
40 N
The force with which the ball hits the catcher's mitt can be calculated using Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m * a
Given that the mass of the softball is 0.2 kilograms and the acceleration is 8 meters per second squared, we can substitute these values into the equation:
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of the softball, m = 0.2 kg
Acceleration, a = 8 m/s^2
Using the formula F = m * a, we can substitute the given values:
F = 0.2 kg * 8 m/s^2
Calculating the product, we get:
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons (N).
To find the force with which the softball will hit the catcher's mitt, we can use Newton's second law of motion which states that the force acting on an object is equal to its mass multiplied by its acceleration.
Given:
Mass of the softball (m) = 0.2 kilograms
Acceleration of the softball (a) = 8 meters per second squared
Using the formula:
Force (F) = mass (m) * acceleration (a)
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.