A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point) Responses 8.2 N 8.2 N 1.6 N 1.6 N 7.8 N 7.8 N 40 N
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a).
Given:
Mass of the softball (m) = 0.2 kg
Acceleration of the softball (a) = 8 m/s²
Using the formula:
F = m * a
Plugging in the given values:
F = 0.2 kg * 8 m/s²
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion: F = ma.
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
Using the formula F = ma, we can substitute the given values:
F = (0.2 kg)(8 m/s^2)
F = 1.6 kg·m/s^2
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To determine the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a). In this case, the mass of the softball is 0.2 kilograms and the acceleration is 8 meters per second squared.
So, we can calculate the force using the formula:
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.