A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point) Responses 40 N 40 N 1.6 N 1.6 N 8.2 N 8.2 N 7.8 N
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law, which states that the force (F) is equal to the mass (m) multiplied by the acceleration (a).
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s²
Using Newton's second law:
F = m * a
Substituting the given values:
F = 0.2 kg * 8 m/s²
Calculating the result:
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 N.
To find the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion.
Newton's second law states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).
In this case, the mass of the softball is given as 0.2 kilograms, and the acceleration is given as 8 meters per second squared.
Using the formula F = ma, we can calculate the force:
F = 0.2 kg * 8 m/s^2
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.