A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?
40 N
7.8 N
1.6 N
8.2 N
The force with which an object hits another object can be calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a).
In this case, the mass of the softball is 0.2 kilograms and the acceleration is 8 meters per second squared.
F = (0.2 kg) * (8 m/s^2)
F = 1.6 N
So, the force with which the ball will hit the catcher's mitt is 1.6 N.
To find the force of the ball hitting the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 0.2 kg
Acceleration (a) = 8 m/s^2
We can substitute these values into the formula:
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 kg*m/s^2
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons (N).
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the softball is given as 0.2 kilograms, and the acceleration it is experiencing is 8 meters per second squared.
So, F = m x a
F = 0.2 kg x 8 m/s^2
F = 1.6 N
Thus, the ball will hit the catcher's mitt with a force of 1.6 Newtons.