A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)
Responses
1.6 N
1.6 N
7.8 N
7.8 N
40 N
40 N
8.2 N
The force with which the ball will hit the catcher's mitt can be calculated using Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). In this case, the mass of the softball is 0.2 kg and the acceleration is 8 m/s^2.
F = m * a
F = 0.2 kg * 8 m/s^2
F = 1.6 kg m/s^2
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.
To calculate the force with which the ball will hit the catcher's mitt, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass of the ball (m) = 0.2 kg
Acceleration (a) = 8 m/s²
Using the formula: F = m * a
F = 0.2 kg * 8 m/s²
F = 1.6 N
Therefore, the force with which the ball will hit the catcher's mitt is 1.6 Newtons.
To calculate the force with which the softball will hit the catcher's mitt, you can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a).
1. First, you need to determine the mass of the softball. The problem states that the softball has a mass of 0.2 kilograms.
2. Next, you need to identify the acceleration of the softball, which is given as 8 meters per second squared.
3. Finally, you can calculate the force by multiplying the mass and acceleration using the formula F = m * a.
Therefore, the force with which the softball will hit the catcher's mitt is:
F = (0.2 kg) * (8 m/s^2) = 1.6 N
So the correct answer is 1.6 N.