A squirrel has stored its across in a hole that is 45 feet from the ground in a tall tree. The squirrel starts on a perch 100 feet above the ground. The squirrel moves from the perch down to its stored acorns in 5.25 seconds. Interpret the quotient to describe the rate of change in the squirrel's height above the ground give your answer to the nearest hundredth.
The rate of change in the squirrel's height above the ground can be interpreted as the speed at which the squirrel is descending from the perch to the stored acorns. To find this rate of change, we divide the change in height by the time taken.
The change in height is given by 100 - 45 = 55 feet (since the squirrel starts at a height of 100 feet and the acorns are stored at a height of 45 feet).
The time taken is given as 5.25 seconds.
Therefore, the rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds ≈ 10.48 feet/second (rounded to the nearest hundredth).
To interpret the quotient, we need to calculate the rate of change in the squirrel's height above the ground. The squirrel starts at a height of 100 feet above the ground and descends to a height of 45 feet above the ground in 5.25 seconds.
The rate of change can be calculated by dividing the change in height by the time it takes. In this case, the change in height is 100 feet - 45 feet = 55 feet. The time it takes is 5.25 seconds.
Therefore, the rate of change in the squirrel's height above the ground is 55 feet / 5.25 seconds = 10.48 feet/second (rounded to the nearest hundredth).
So, the squirrel descends at an average rate of approximately 10.48 feet per second.
To interpret the quotient that describes the rate of change in the squirrel's height above the ground, we need to divide the change in height by the time it took for the squirrel to move.
First, let's calculate the change in height. The squirrel started on a perch 100 feet above the ground and moved down to its stored acorns, which are in a hole 45 feet from the ground. Therefore, the change in height is 100 - 45 = 55 feet.
Next, we can calculate the rate of change by dividing the change in height by the time it took. The squirrel took 5.25 seconds to move. So, the rate of change is 55 feet / 5.25 seconds = 10.48 feet/second.
Therefore, the rate of change in the squirrel's height above the ground is approximately 10.48 feet/second, rounded to the nearest hundredth.